An organic acid was analyzed and the following percent composition was obtained: 68.85% Carbon, 4.9% hydrogen, 26.2 Oxygen. A solution of 1.02 g of this compound dissolves in 10.0 g of benzene freezes at 3.37 degrees C. The normal freezing point of benzene us 5.50 degrees C and it has a Kf of 5.12 C/m. Determine the molecular formula for this compound.

answer

watching

471

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Reid WolffLv2

13 Dec 2019

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

Join us on Discord

Chemistry Study Group

Join now

Related questions

Pheromones are compounds secreted by the females of many insect species to attract males. One of these compounds contains 80.78 percent carbon, 13.56 percent hydrogen, and 5.66 percent oxygen. A solution of 1.00 g of this pheromone in 8.50 g of benzene freezes at 3.37ÂºC. What are the molecular formula and molar mass of the compound? (The normal freezing point of pure benzene is 5.50ÂºC.) K_f = 5.12 ÂºC /m

When 2.67 grams of an unknown organic compound with the % composition shown below is dissolved in 65.3 g camphor, the freezing point of the solution is 159.2Â°C. Determine the molecular formula of the compound.

Element % by mass in unknown Carbon 39.12 Hydrogen 8.76 Oxygen 52.12

Help!