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11 Dec 2019
1) Rank the following titrations in order of increasing pH at the halfway point to equivalence (1 = lowest pH and 5 = highest pH).
1 2 3 4 5 200.0 mL of 0.100 M HC2H3O2 (Ka = 1.8 x 10-5) by 0.100 M NaOH
1 2 3 4 5 200.0 mL of 0.100 M H2NNH2 (Kb = 3.0 x 10-6) by 0.100 M HCl
1 2 3 4 5 100.0 mL of 0.100 M HF (Ka = 7.2 x 10-4) by 0.100 M NaOH
1 2 3 4 5 200.0 mL of 0.100 M (C2H5)2NH (Kb = 1.3 x 10-3) by 0.100 M HCl
1 2 3 4 5 100.0 mL of 0.100 M HCl by 0.100 M NaOH
1) Rank the following titrations in order of increasing pH at the halfway point to equivalence (1 = lowest pH and 5 = highest pH).
1 2 3 4 5 200.0 mL of 0.100 M HC2H3O2 (Ka = 1.8 x 10-5) by 0.100 M NaOH
1 2 3 4 5 200.0 mL of 0.100 M H2NNH2 (Kb = 3.0 x 10-6) by 0.100 M HCl
1 2 3 4 5 100.0 mL of 0.100 M HF (Ka = 7.2 x 10-4) by 0.100 M NaOH
1 2 3 4 5 200.0 mL of 0.100 M (C2H5)2NH (Kb = 1.3 x 10-3) by 0.100 M HCl
1 2 3 4 5 100.0 mL of 0.100 M HCl by 0.100 M NaOH
Jean KeelingLv2
13 Dec 2019