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11 Dec 2019

Glucose has a solubility of 91 g/100 mL of water at 25 oC. How does this solubility compare to the solubility of NH4Cl in water? A. The solubility of ammonium chloride is higher. B. They both have the same solubility C. The solubility of glucose is higher. D. This cannot be determined from the data collected here.

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Patrina SchowalterLv2

13 Dec 2019

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Related questions

Potassium and sodium chloride are similar in charge and they both have the same anion. When comparing sodium chloride ( at ) and potassium chloride, which has a higher solubility at ?

A. potassium chloride B. This cannot be determined from the data collected here. C. sodium chloride D. They are both equally soluble.

bluedonkey507

1. Record your results for the four solubilitytemperatures of KCl as follows:

a. Temperature atwhich the solubility is 3.5g / 10 mL (C): 23.2C

b. Temperature atwhich the solubility is 4g / 10 mL (C): 39.5C

c. Temperature atwhich the solubility is 4.5g / 10 mL (C): 57.2C

d. Temperature atwhich the solubility is 5g / 10 mL (C): 73.5C

2. Convert your grams/10 mL values to grams/100 mLvalues and plot a solubility curve for potassium chloride. Thehorizontal axis is the temperature scale from 20 to 80C using10-degree intervals, and the vertical scale is the solubility ing/100 mL.

3. Here is the official solubility data for KCl ingrams/100 mL H2O:

At 30C: 37.1g / 100 mLH2O

At 50C: 42.9g / 100 mLH2O

At 70C: 48.5g / 100 mLH2O

At 90C: 53.8g / 100 mLH2O

Plot these points on a new graph. Identify the two linesas "experimental" and "official."

4. Obtain the solubility of potassium chloride in g/100mL of H2O at 60C from both the official and experimental solubilitycurves and record them here.

Calculate the percent difference between the two valuesusing the formula:

% difference = |official value - experimental value| /official value * 100%

Experiment2

Record your results for the four solubility temperaturesof NH4Cl as follows:

a.Temperature at which the solubility is 4.0 g / 10 mL (C):26.1C

b.Temperature at which the solubility is 4.5 g / 10 mL (C):37.4C

c.Temperature at which the solubility is 5.0 g / 10 mL (C):49.1C

d.Temperature at which the solubility is 6.0 g / 10 mL (C):68.4C

2. Convert your grams/10 mL values to grams/100 mLvalues and plot a solubility curve for ammonium chloride. Thehorizontal axis is the temperature scale from 20 to 80C using10-degree intervals, and the vertical scale is the solubility ing/100 mL.

3. In the experiments conducted here, what was thesolvent?

Answer and why?