Question

James Watt once observed that a hard-working horse can lift a 330 lb mass 100 ft in 1 min. Assuming the horse generates energy to accomplish this work by metabolizing glucose: C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(l)C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(l) How much (in gram) glucose must a horse metabolize to sustain this rate of work for 1 hour, if the temperature is 250C250C? (1 lb = 0.4536 kg, 1 ft = 0.305 m, g=9.81 ms2ms2)