I did a titration with HCL in the buret, and a saturated solution of Ca(OH)2 that was prepared with 0.2M CaCl2. I understand how to calculate solubility in water, but how do I calculate the molar solubility of Ca(OH)2 in 0.2M CaCl2.

Here is what I have

Trial #1

Volume of Ca(OH)2- 10.00 ml

Initial Buret Reading- 15.85 ml

Final Buret Reading- 22.25 ml

Volume of HCL Delivered- 6.40 ml

Can someone please explain how to calculate the solubility based off of this data. Please show steps so I can do the second trial!!! Thank you!

Question

I did a titration with HCL in the buret, and a saturated solution of Ca(OH)2 that was prepared with 0.2M CaCl2. I understand how to calculate solubility in water, but how do I calculate the molar solubility of Ca(OH)2 in 0.2M CaCl2.

Here is what I have

Trial #1

Volume of Ca(OH)2- 10.00 ml

Initial Buret Reading- 15.85 ml

Final Buret Reading- 22.25 ml

Volume of HCL Delivered- 6.40 ml

Can someone please explain how to calculate the solubility based off of this data. Please show steps so I can do the second trial!!! Thank you!

B. Molar Solubility of Calcium Hydroxide in the Presence of a Common Ion
	Trial 1	Trial 2
1. Volume of saturated Ca(OH)₂ with added CaCl₂ solution (mL)	25	25
2. Concentration of standardized HCl solution (mol/L)	0.0465
3. Buret reading, initial (mL)	0	0
4. Buret reading, final (mL)	39.4	42.6
5. Volume of HCl added (mL)	39.4	42.6
6. Moles of HCl added (mol)	0.00183	0.00198
7. Moles of OH^- in saturated solution (mol)	0.0366	0.0396
8. [OH-], equilibrium (mol/L)	0	0.0238
9. Molar solubility of Ca(OH)₂ with added CaCl₂ (mol/L)
10. Average molar solubility of Ca(OH)₂ with added CaCl₂ (mol/L)

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