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11 Dec 2019

You have a 250mM stock solution of NaCl (Formula Weight: 58.4g/mole), a 0.05M stock solution of glucose (Formula Weight; 180.2g/mole), a bottle of alanine, solid form (Formula Weight: 89.09g/mole), and a bottle of Tris base, solid form (Formula Weight: 121.1g/mole). How would you prepare 150mL of a single solution containing 50mM Tris, 25mM glucose, 0.015M NaCl, and 1.5% (w/v) alanine. SHOW ALL WORK AND CALCULATIONS! !!!

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Keith Leannon
Keith LeannonLv2
13 Dec 2019

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