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11 Dec 2019
Consider the titration of 70.0 mL of 0.0300 M NH3 (a weak base; Kb = 1.80e-05) with 0.100 M HCl. Calculate the pH after the following volumes of titrant have been added:
(a) 0.0 mL
pH =
(b) 5.3 mL
pH = (c) 10.5 mL
pH = (d) 15.8 mL
pH =
(e) 21.0 mL
pH =
(f) 35.7 mL
pH =
Consider the titration of 70.0 mL of 0.0300 M NH3 (a weak base; Kb = 1.80e-05) with 0.100 M HCl. Calculate the pH after the following volumes of titrant have been added:
(a) 0.0 mL pH = | (b) 5.3 mL pH = | (c) 10.5 mL pH = |
(d) 15.8 mL pH = | (e) 21.0 mL
| (f) 35.7 mL pH = |
Sixta KovacekLv2
13 Dec 2019