0
answers
0
watching
106
views
12 Dec 2019

A) The activation energy of a certain reaction is 34.8 kJ/mol . At 28 ∘C , the rate constant is 0.0120s−1. At what temperature in degrees Celsius would this reaction go twice as fast?

B) Given that the initial rate constant is 0.0120s−1 at an initial temperature of 28 ∘C , what would the rate constant be at a temperature of 160. ∘C for the same reaction described in Part A

For unlimited access to Homework Help, a Homework+ subscription is required.

discord banner image
Join us on Discord
Chemistry Study Group
Join now

Related textbook solutions

Weekly leaderboard

Start filling in the gaps now
Log in