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12 Dec 2019

Constant Value
Ecu 0.337
Ezn -7.63
R 8.314
F 96,485
T 298

In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for the following redox reaction that occurs in an electrochemical cell having two electrodes: a cathode and an anode. The two half-reactions that occur in the cell are

Cu2+(aq)+2e−→Cu(s) and Zn(s)→Zn2+(aq)+2e−

The net reaction is

Cu2+(aq)+Zn(s)→Cu(s)+Zn2+(aq)

Use the given standard reduction potentials in your calculation as appropriate.

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Elin Hessel
Elin HesselLv2
13 Dec 2019

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Related questions

Constants

The following values may be useful when solving this tutorial.

Constant Value
E∘Cu 0.337 V
E∘Ni -0.257 V
R 8.314 J⋠mol−1⋠K−1
F 96,485 C/mol
T 298 K

Part A

In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for the following redox reaction that occurs in an electrochemical cell having two electrodes: a cathode and an anode. The two half-reactions that occur in the cell are

Cu2+(aq)+2e−→Cu(s) and Ni(s)→Ni2+(aq)+2e−

The net reaction is

Cu2+(aq)+Ni(s)→Cu(s)+Ni2+(aq)

Use the given standard reduction potentials in your calculation as appropriate.

Constants

The following values may be useful when solving this tutorial.

Constant Value
E∘Cu 0.337 V
E∘Co -0.277 V
R 8.314 J⋠mol−1⋠K−1
F 96,485 C/mol
T 298 K

Part A

In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for the following redox reaction that occurs in an electrochemical cell having two electrodes: a cathode and an anode. The two half-reactions that occur in the cell are

Cu2+(aq)+2e−→Cu(s) and Co(s)→Co2+(aq)+2e−

The net reaction is

Cu2+(aq)+Co(s)→Cu(s)+Co2+(aq)

Use the given standard reduction potentials in your calculation as appropriate.

Express your answer numerically to three significant figures.
Keq =

The following values may be useful when solving this tutorial. Constant Value E∘Cu 0.337 V E∘Co -0.277 V R 8.314 J⋠mol−1⋠K−1 F 96,485 C/mol T 298 K

Part A

The two half-reactions that occur in the cell are Cu2+(aq)+2e−→Cu(s) and Co(s)→Co2+(aq)+2e− The net reaction is Cu2+(aq)+Co(s)→Cu(s)+Co2+(aq) Use the given standard reduction potentials in your calculation as appropriate. Express your answer numerically to three significant figures.
Keq =

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