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12 Dec 2019

For an enzymatically catalyzed reaction in which the measured values for KM and Vmax are, respectively, 6.20 mM and 1.02 mM min-1, what is the value of the turnover number? The concentration of enzyme used in the reaction is 50.0 μM. turnover number =

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Sixta Kovacek
Sixta KovacekLv2
13 Dec 2019

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