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12 Dec 2019
To solve stoichiometry problems, you must always calculate numbers of moles. Recall that molarity, M, is equal to the concentration in moles per liter: M=mol/L.
When solutions of silver nitrate and calcium chloride are mixed, silver chloride precipitates out of solution according to the equation 2AgNO3(aq)+CaCl2(aq)â2AgCl(s)+Ca(NO3)2(aq)
Part A
What mass of silver chloride can be produced from 1.55 L of a 0.183 M solution of silver nitrate?
Express your answer with the appropriate units.
Hints
mass of AgCl =
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Part B
The reaction described in Part A required 3.24 L of calcium chloride. What is the concentration of this calcium chloride solution?
Express your answer with the appropriate units.
Hints
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To solve stoichiometry problems, you must always calculate numbers of moles. Recall that molarity, M, is equal to the concentration in moles per liter: M=mol/L. | When solutions of silver nitrate and calcium chloride are mixed, silver chloride precipitates out of solution according to the equation 2AgNO3(aq)+CaCl2(aq)â2AgCl(s)+Ca(NO3)2(aq) Part A What mass of silver chloride can be produced from 1.55 L of a 0.183 M solution of silver nitrate? Express your answer with the appropriate units. Hints
SubmitMy AnswersGive Up Part B The reaction described in Part A required 3.24 L of calcium chloride. What is the concentration of this calcium chloride solution? Express your answer with the appropriate units. Hints
SubmitMy AnswersGive Up |
Trinidad TremblayLv2
13 Dec 2019