The decomposition reaction SO2Cl2(g) â SO2(g) + Cl2(g) is first order, with a rate constant of 2.2 Ã 10â5 s â1 at 320Â°C. The partial pressure of SO2Cl2(g) in a sealed vessel at 320Â°C is initially 1.0 atm. How long will it take for the partial pressure of SO2Cl2(g) to fall to 0.50 atm?

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Jarrod RobelLv2

13 Dec 2019

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Related questions

2) SO2Cl2 decomposes in the gas phase by the reaction
SO2Cl2 (g) ? SO2 (g) + Cl2 (g)
The reaction is first order in SO2Cl2 and the rate constant is 3.0Ã 10-6 s-1at 600 K. A vessel is charged with
3.3 atm of SO2Cl2 at 600 K. The partial pressure of SO2 at 3.0 Ã105 s is __________ atm.
A) 3.7 B) 2.0 C) 2.1 D) 1.3 E) 3.0

SO2Cl2 - SO2+Cl2

The reaction is the first oreder SO2Cl2 and the rate constant is3.0x10^-6 at 600K. A vessel is charged with 3.3 atm of SO2Cl2 at600k. The partial pressure of SO2 at 3.0x10^5seconds is_____atm.

Answers

a. 3.0

b 1.3

c. 2.1

d 2.0

e 3.7

mauvewhale711

The decomposition of sulfuryl chloride, SO₂Cl₂, to sulfur dioxide and chlorine gases is a first-order reaction.

At a certain temperature, the half-life of SO₂Cl₂ is 7.5 × 10² min. Consider a sealed flask with 122.0 g of SO₂Cl₂. (a) How long will it take to reduce the amount of SO₂Cl₂ in the sealed flask to 45.0 g? (b) If the decomposition is stopped after 29.0 h, what volume of Cl₂ at 27°C and 1.00 atm is produced?