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13 Dec 2019

A) 36.84 mL of 0.1184 M NaOH is required to titrate 33.45 mL of HCl to endpoint. What is the HCl concentration?

B) If a 0.1 g portion of soda ash requires 13.56 mL of HCL to titrate it to endpoint, how many grams of soda ash should be used to get approximate titrant volume of 35-40 mL?

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Sixta KovacekLv2

17 Dec 2019

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Please help with the last two parts!!

1.A 1.478 g sample of soda ash required 17.41 mL of 0.6714 MHCl to reach the second endpoint. Determine the % Na₂CO₃in the soda ash sample.

0.6714 M X 0.01741 L = 0.01169 mol HCl

0.01169 mol HCl X X = 0.6195 g Na₂CO₃

( 0.6195 g Na₂CO₃/ 1.478 g Na₂CO₃) X 100 = 41.91% Na₂CO₃

2.A particular soda ash sample contains 20.33% Na₂CO₃. How many mL of 0.4009 MHCl would be required to neutralize a 1.559 g of this soda ash sample?

3.Letâs suppose you didnât follow the procedure and failed to quantitatively transfer the soda ash sample to the Erlenmeyer flask. How would this specifically affect your calculated percentage of Na₂CO₃?

A student determined their NaOH molarity to be 0.0943 M. This solution was used to standardize 25.00 mL of an HCl solution, requiring 25.73 mL to reach the equivalence point. The HCl solution was then used to determine the weight % of soda ash in 0.5102 g of an unknown sample, requiring 38.77 mL. If the determined NaOH concentration was 5.000% too low (relative error of -5%), how does it change the reported value of weight % soda ash?

1. Calculate the volume in mL of a 0.50 M NaOH solution that will be required to titrate 1.2 g of potassium hydrogen phthalate to the phenolphthalein end point. The molar mass of KHP is 204.2 g/mol

2. It takes 12.45 mL of 0.50 M NaOH to back titrate a mixture containing 1.25 g of baking soda, NaHCO₃, and 10.00 mL of 1.2 M HCl solution. Calculate the moles of antacid activity (OH^-) per gram of baking soda.

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A) 36.84 mL of 0.1184 M NaOH is required to titrate 33.45 mL of HCl to endpoint. What is the HCl concentration?

B) If a 0.1 g portion of soda ash requires 13.56 mL of HCL to titrate it to endpoint, how many grams of soda ash should be used to get approximate titrant volume of 35-40 mL?

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A) 36.84 mL of 0.1184 M NaOH is required to titrate 33.45 mL of HCl to endpoint. What is the HCl concentration? B) If a 0.1 g portion of soda ash requires 13.56 mL of HCL to titrate it to endpoint, how many grams of soda ash should be used to get approximate titrant volume of 35-40 mL?

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Related textbook solutions

Basic Chemistry

Principles of Chemistry Molecular Approach

Chemistry: Structure and Properties

Principles of Chemistry Molecular Approach

Chemistry: A Molecular Approach

Chemistry: A Molecular Approach

Principles of Chemistry: A Molecular Approach

Chemistry: The Central Science

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A) 36.84 mL of 0.1184 M NaOH is required to titrate 33.45 mL of HCl to endpoint. What is the HCl concentration?

B) If a 0.1 g portion of soda ash requires 13.56 mL of HCL to titrate it to endpoint, how many grams of soda ash should be used to get approximate titrant volume of 35-40 mL?