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13 Dec 2019

The rate constant of a chemical reaction increased from 0.100 s−1 to 3.00 s−1 upon raising the temperature from 25.0 ∘C to 43.0 ∘C . Part A Calculate the value of (1T2−1T1) where T1 is the initial temperature and T2 is the final temperature.

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Nelly Stracke
Nelly StrackeLv2
17 Dec 2019

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Related questions

The rate constant of a chemical reaction increased from 0.100 to 3.10 upon raising the temperature from 25.0 to 51.0. Calculate the value of 1/t2-1/t1

The rate constant of a chemical reaction increased from 0.100s?1 to 3.20s?1 upon raising the temperature from 25.0 ?C to 49.0?C.

Part A

Calculate the value of (1T2?1T1) whereT1 is the initial temperature and T2 is the finaltemperature.

Express your answer numerically.

Part B

Calculate the value of ln(k1k2) wherek1 and k2 correspond to the rate constants at theinitial and the final temperatures as defined in part A.

Express your answer numerically.

Part C

What is the activation energy of the reaction?

Express your answer numerically in kilojoules per mole.

The rate constant of a chemical reaction increased from 0.100 S^-1to 2.90 S^-1 upon raising the temperature from 25.0 C to 43.0C.

Calculate the values of ((1/T2)-(1/T1)), ln(k2/k1), and theactivation energy of the reaction.

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