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Identify the acid, the base, the conjugate acid and the conjugate base in the following equation:CH3COOH (aq) + H2O (l) --> H3O+(aq) + CH3COO-(aq)A. CH3COOH is the acid; H2O is the base, H3O+ is the conjugate acid and CH3COO- is the conjugate baseB. CH3COOH is the conjugate acid; H2O is the conjugate base, H3O+ is the acid and CH3COO- is the baseC. CH3COOH is the base; H2O is the acid, H3O+ is the conjugate base and CH3COO- is the conjugate acidD. The equation above cannot occur because water is not an acid or a base.
Identify the acid, the base, the conjugate acid and the conjugate base in the following equation:CH3COOH (aq) + H2O (l) --> H3O+(aq) + CH3COO-(aq)A. CH3COOH is the acid; H2O is the base, H3O+ is the conjugate acid and CH3COO- is the conjugate baseB. CH3COOH is the conjugate acid; H2O is the conjugate base, H3O+ is the acid and CH3COO- is the baseC. CH3COOH is the base; H2O is the acid, H3O+ is the conjugate base and CH3COO- is the conjugate acidD. The equation above cannot occur because water is not an acid or a base.
Beverley SmithLv2
17 Dec 2019
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