1
answer
0
watching
39
views
13 Dec 2019
A scientist measures the standard enthalpy change for the following reaction to be 2871.0 kJ : 6CO2(g) + 6 H2O(l)C6H12O6 + 6 O2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is kJ/mol.
A scientist measures the standard enthalpy change for the following reaction to be 2871.0 kJ : 6CO2(g) + 6 H2O(l)C6H12O6 + 6 O2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is kJ/mol.
Sixta KovacekLv2
17 Dec 2019