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13 Dec 2019

When 20.0 mL of 1.0 M H3PO4 is added to 60.0 mL of 1.0 M NaOH at 25.0 degrees celcius in a calorimeter, the temperature of the aqueous solution increases to 35.0 degrees celcius.

Assuming that the specific heat of the solution is 4.18 J/(g⋠∘C), that its density is 1.00 g/mL, and that the calorimeter itself absorbs a negligible amount of heat, calculate ΔH in kilojoules/mol H3PO4 for the reaction.

H3PO4(aq)+3NaOH(aq)→3H2O(l)+Na3PO4(aq)

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Deanna Hettinger
Deanna HettingerLv2
17 Dec 2019

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