Question

PART A:Click the DeltaH is an Extensive Property button within the activity, and analyze the relationship between the two reactions that are displayed. The reaction that was on the screen when you started and its derivative demonstrate that the change in enthalpy for a reaction, ΔH, is an extensive property. Using this property, calculate the change in enthalpy for Reaction 2. Reaction 1: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g), ΔH1=−2043 kJ Reaction 2: 4C3H8(g)+20O2(g)→12CO2(g)+16H2O(g), ΔH2=? Express your answer to four significant figures and include the appropriate units.

PART B: analyze the relationship between the two reactions that are displayed. The reaction that was on the screen when you started and its derivative demonstrate that the reaction enthalpy, ΔH, changes sign when a process is reversed. Consider the reaction B(s)+32O2(g)→B2O3(s), ΔH =−1270kJ

PART C:What will ΔH be for the reaction if it is reversed? alculate the reaction enthalpy, ΔH, for the following reaction: CH4(g)+2O2(g)→CO2(g)+2H2O(l)Use the series of reactions that follow: C(s)+2H2(g)→CH4(g), ΔH =−74.8 kJ. C(s)+O2(g)→CO2(g), ΔH =−393.5 kJ. 2H2(g)+O2(g)→2H2O(g), ΔH =−484.0 kJ. H2O(l)→H2O(g), ΔH =44.0 kJ. Express your answer with appropriate units.