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13 Dec 2019
The quantity t1/2=? ln 2 is called the half-life of an exponential decay, where ?=RC is the time constant in an RC circuit. The current in a discharging RC circuit drops by half whenever t increases by t1/2. For a circuit with R=1 k? and C=5 ?F, if the current is 6 mA at t=5 ms, at what time (in ms) will the current be 3 mA?
The quantity t1/2=? ln 2 is called the half-life of an exponential decay, where ?=RC is the time constant in an RC circuit. The current in a discharging RC circuit drops by half whenever t increases by t1/2. For a circuit with R=1 k? and C=5 ?F, if the current is 6 mA at t=5 ms, at what time (in ms) will the current be 3 mA?
Jamar FerryLv2
17 Dec 2019