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. A solution is prepared with 0.155M KCOOH (potassium formate) and 0.200M HCOOH (formic acid). We are told that Ka = 1.8 x 10- 4 for HCOOH. Calculate the pH of this solution, using an ICE table. (6pts) Two dissociation eqns: Ka expression: Conc.(M) Initial Change Equilibrium
. A solution is prepared with 0.155M KCOOH (potassium formate) and 0.200M HCOOH (formic acid). We are told that Ka = 1.8 x 10- 4 for HCOOH. Calculate the pH of this solution, using an ICE table. (6pts) Two dissociation eqns: Ka expression: Conc.(M) Initial Change Equilibrium
Deanna HettingerLv2
17 Dec 2019
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