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13 Dec 2019

A wastewater treatment operator has been fined because the DO at a point 6 km downstream is below the permit limit of 5 mg/L. Determine the highest BODu concentration possible in the effluent which can still achieve the permitted requirement of a DO greater than 5 mg/L year round.



QR = 13.8 m3/s

QW = 4.4 m3/s

TW Summer = 30°C

TR Summer = 22°C

TW Winter = 13°C

TR Winter = 7°C

kBOD@20° = 0.4 d-1 (assume KBOD is the same for the river and effluent)

H =4 m (assume no change due to wastewater flow)

V = 0.03 m/s (assume no change due to wastewater flow)

DOR = 7 mg/L

DOW = 1 mg/L

BODR = 5 mg/L

n = 0.4

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