answer

watching

views

13 Dec 2019

Some compounds of hydrogen and oxygen are exceptions to the common observation that H has an oxidation number +1 and that O has oxidation number -2. Assuming that the metal has the oxidation number of its most common ion, find the oxidation number of H in the compound LiAlH₄.

answer

watching

199

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Nelly StrackeLv2

17 Dec 2019

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

Join us on Discord

Chemistry Study Group

Join now

Related questions

Oxidation states are important for keeping track of electrons in oxidation-reduction reactions. Here are some general rules to remember:

In most cases, oxygen has an oxidation state of ?2.
Group 1 and group 2 elements on the periodic table have +1 and +2 oxidation states, respectively.
In most cases, hydrogen has an oxidation state of +1.
Many elements can have more than one oxidation state. In such cases, use the other elements in the compound whose oxidation states are known to determine the oxidation state of the element that varies.

Neutral compounds

In a neutral compound, the sum of the oxidation states is zero. Note that the sign of the oxidation states and the number of atoms associated with each oxidation state must be considered. In H2O, for example, each hydrogen atom has an oxidation state of +1 and each oxygen atom has an oxidation state of ?2 for a total of 2(+1)+(?2)=0.

Part A

What is the oxidation state of an individual carbon atom in CaCO3?

Express the oxidation state numerically (e.g., +1).

SubmitHintsMy AnswersGive UpReview Part

Part B

What is the oxidation state of an individual nitrogen atom in HNO3?

Express the oxidation state numerically (e.g., +1).

SubmitHintsMy AnswersGive UpReview Part

Ions

In an ion, the sum of the oxidation states is equal to the overall ionic charge. Note that the sign of the oxidation states and the number of atoms associated with each oxidation state must be considered. In OH?, for example, the oxygen atom has an oxidation state of ?2 and the hydrogen atom has an oxidation state of +1, for a total of (?2)+(+1)=?1.

Part C

What is the oxidation state of an individual sulfur atom in SO32??

Express the oxidation state numerically (e.g., +1).

SubmitHintsMy AnswersGive UpReview Part

Part D

What is the oxidation state of each individual carbon atom in C2O42??

Express the oxidation state numerically (e.g., +1).

Neutral compounds In a neutral compound, the sum of the oxidation states is zero. Note that the sign of the oxidation states and the number of atoms associated with each oxidation state must be considered. In H2O, for example, each hydrogen atom has an oxidation state of +1 and each oxygen atom has an oxidation state of â2 for a total of 2(+1)+(â2)=0.

Part A:

What is the oxidation state of an individual sulfur atom in BaSO4? Express the oxidation state numerically (e.g., +1).

Part B

What is the oxidation state of an individual nitrogen atom in HNO3? Express the oxidation state numerically (e.g., +1).

In an ion, the sum of the oxidation states is equal to the overall ionic charge. Note that the sign of the oxidation states and the number of atoms associated with each oxidation state must be considered. In OHâ, for example, the oxygen atom has an oxidation state of â2 and the hydrogen atom has an oxidation state of +1, for a total of (â2)+(+1)=â1.

Part C:

What is the oxidation state of an individual phosphorus atom in PO33â? Express the oxidation state numerically (e.g., +1).

Part D:

What is the oxidation state of each individual carbon atom in C2O42â?