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18 Dec 2019

Please please help me, im struggling with this so much!

Calculate the change in pH to 0.01 pH units caused by adding 10. mL of 3.57-M NaOH is added to 330. mL of each of the following solutions.

b) 0.194 M NH41+

pH before mixing =
pH after mixing=
pH change =

c) 0.194 M NH3

pH before mixing =
pH after mixing=
pH change =

d) a buffer solution that is 0.194 M in each NH41+ and NH3

pH before mixing =
pH after mixing=
pH change =

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Jean Keeling
Jean KeelingLv2
31 Dec 2019

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Related questions

Show all work NO HAND WRITTEN RESPONSES TYPED ONLY.

A buffer is made by mixing 50.0 mL of .10 M acetic acid and 50.0 mL of 0.25 M potassium acetate.

QUESTION: Calculate the pH of the buffer solution and Calculate the pH of the buffer solution after adding 1.0 mL of 3.0 M NaOH

CONSIDER: IF the NaOH were added to 100.0 mL of pure water what would the pH result be?

Can someone walk me through this please? Struggling a little bit:

What is the pH of a solution made by mixing 30.00 mL of 0.10 M acetic acid with 0.10 M KOH? Assume that the volumes of the solutions are additive. Ka = 1.8 × 10-5 for CH3CO2H. (7 points each)

A. What is the pH of the solution before the addition of base?

B. What is the pH of the solution following the addition of 10 ml of base?

C. What is the pH of the solution at the equivalence point?

A buffer solution is prepared by mixing 50.0 mL of 0.300 M NH3 with50.0 mL of 0.300 M NH4Cl. the pKb is 4.74.


NH3 + H2O ? NH4+ + OH -

a) Calculate the [NH3] and [H4Cl] in the buffer solution. Calculatethe pH of the buffer solution.


b) 7.50 mL of 0.125 M HCl is added to the 100.0 mL of the buffersolution. Calculate the new [NH3] and [NH4Cl] for the buffersolution. Calculate the new pH of the solution


c) 7.50 mL of 0.125 M NaOH is added to the 100.0 mL of the buffersolution. Calculate the new [NH3] and [NH4Cl] for the buffersolution. Calculate the new pH of the solution.


***Please give a thorough step-by-step solution for each part.Please include all units in your work so I can keep track of whateverything is measured in! Thanks!***


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