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18 Dec 2019

How many grams of aluminum chloride, AlCl3, can be produced from 25.0 g of chlorine when more than enough aluminum is present for the reaction? Al(s) + Cl2 (g) ---> AlCl3 (s) (needs to balance)

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Jamar Ferry
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31 Dec 2019

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Related questions

An electrolytic cell is constructed to produce aluminum metaland chlorine gas from aluminum chloride (AlCl3).
A. Write the half-reaction that occurs at the anode:

B. Write the half-reaction that occurs at the cathode.

C. Write the balanced equation for the net reaction.

D. Calculate the standard cell potential (E?cell).

E. How many grams of aluminum metal and how many liters of chlorinegas can be produced by passage of 4.8 amp of current for 2.3 hourunder standard conditions (25?C and 1 atm pressure)?

1) 1.15 g H2 is allowed to react with 9.70 g N2, producing 2.73 g NH3

Part A

What is the theoretical yield in grams for this reaction under the given conditions?

Part B

What is the percent yield for this reaction under the given conditions?

2) Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction:

2Al(s)+3Cl2(g)→2AlCl3(s)

* amount of moles aluminum chloride could be produced from 39.0g of chlorine gas, Cl2---> 0.367 mol (not sure if necessary)

What is the maximum mass of aluminum chloride that can be formed when reacting 34.0 g of aluminum with 39.0 g of chlorine?

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction:

2Al(s)+3Cl2(g)→2AlCl3(s)

You are given 19.0 g of aluminum and 24.0 g of chlorine gas.

If you had excess chlorine, how many moles of of aluminum chloride could be produced from 19.0 g of aluminum? Express your answer to three significant figures and include the appropriate units.

If you had excess aluminum, how many moles of aluminum chloride could be produced from 24.0 g of chlorine gas, Cl2? Express your answer to three significant figures and include the appropriate units.

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