A piece of plastic weighing 1.157 g has a volume of 1.48 cm³. A piece of wood has the same volume but weighs 3.85 g. The density of liquid X is 0.765 g/mL and the density of liquid Z is 1.13 g/mL. The two liquids are immiscible. If the plastic and wood are added to the two liquids, what is the order of layers from top to bottom in the container?

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goldserval389Lv1

2 Jun 2021

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This question has multiple parts. Work all the parts to get the most points.

You want to determine the density of a compound but have only a tiny crystal, and it would be difficult to measure mass and volume accurately. There is another way to determine density, however, called the flotation method. If you placed the crystal in a liquid whose density is precisely that of the substance, it would be suspended in the liquid, neither sinking to the bottom of the beaker nor floating to the surface. However, for such an experiment, you would need to have a liquid with the precise density of the crystal. You can accomplish this by mixing two liquids of different densities to create a liquid having the desired density. Consider the following: you mix 8.90 mL of CHCl₃ (d = 1.492 g/mL) and 6.70 mL of CHBr₃ (d = 2.890 g/mL), giving 15.6 mL of solution. What is the density of this mixture?

g/mL

Correct

Mass CHCl₃ = 8.90 mL Ã 1.492 g/mL = 13.3 g

Mass CHBr₃ = 6.70 mL Ã 2.890 g/mL = 19.4 g

Mass of solution = 13.3 g + 19.4 g = 32.6 g

Volume of solution = 8.90 mL + 6.70 mL = 15.6 mL

(It is important that you postpone rounding until all the calculations are completed. At least one extra digit beyond the significant digits should be carried through all of the computations in order to avoid a rounding error. Round only the final answer to the correct number of significant digits.)

Suppose now that you wanted to determine the density of a small yellow crystal to confirm that it is silicon. From the literature, you know that silicon has a density of 2.33 g/cm³. How would you prepare 20.0 mL of the liquid mixture having that density from pure samples of CHCl₃ (d = 1.492 g/mL) and CHBr₃ (d = 2.890 g/mL)? (Note: 1 mL = 1 cm³.)

V(CHCl₃) = mL

V(CHBr₃) = mL

1) A glass vessel calibrated to contain 9.76 mL at 4degree C was found to weigh 22.624 g when empty and dry. Filled with a soduim chloride (NaCl) solution at the same temperature , it was found to weigh 32.770 g. Calculate the solution's density.

2) the melting point of lauric acid and stearic acid are 43 degrees and 70 degrees C respectively. Are they solids liquids or gases at room temperature?

3) When water (d= 1.00/mL) and dichloromethane (d= 1.34 g/mL) are mixed, two layers are formed. which liquid is in the lower layer?

4) Which has the greater volume: 10g of hexane (d=0.66g/mL) or 10 g of toluene (d=0.87g/mL)? What is the voulme of each?

Please Explain