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Combustion analysis of a compound known to contain just C, H, N, and O demonstrated that it is 46.21 wt% C, 9.02 wt % H,13.74 wt% N, and, by difference, 100 - 46.21 - 9.0213.74 = 31.03 wt% O. This means that 100 g of the unknown would contain 46.21 g of C, 9.02 g of H, and so on. Find the atomic ratio C:H:N:O and express it as the lowest reasonable integer ratio.

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