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(a) What does the term diamagnetism mean? (b) How does a diamagnetic substance respond to a magnetic field? (c) Which of the following ions would you expect to be diamagnetic: N22 -, O22 -, Be22 + , C2–?

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Hubert Koch
Hubert KochLv2
22 May 2020

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Related questions

The C2 molecule exists in the vapor phase over carbon at high temperature. Describe the molecular orbital structure of this molecule; that is, give the orbital diagram and electron configuration. Would you expect the molecular substance to be diamagnetic or paramagnetic? What is the bond order for C2?

Explain the following: (a) The peroxide ion, O22- , has a longer bond length than the superoxide ion, O2-. (b) The magnetic properties of B2 are consistent with the π2p MOs being lower in energy than the σ2p MO. (c) The O22 + ion has a stronger O—O bond than O2 itself.

The bond order is:
½ (number of bonding el. – number of antibonding el.) = ½ (8 – 6) = 1

Superoxide ion has 13 valence electrons, and one electron less in antibonding orbitals. Electron configuration of O2- ion is

The bond order is:
½ (number of bonding el. – number of antibonding el.) = ½ (8 – 5) = 1.5

The longer bond length of peroxide ion is in accordance with the lower bond order.

b) B2 molecule has 6 valence electrons. Two possible electron configurations are:

1) When σ2p MO is lower in energy:

If this is the correct el. configuration, molecule would have no unpaired electrons and would be diamagnetic.

2) When π2p orbitals are lower in energy

In this case, two energetically equivalent π2p orbitals are filled with one electron, according to Hund’s rule. As a result, the molecule is a paramagnetic with two unpaired electrons.

c) O22+ ion has 10 valence electrons, and the el. configuration:

The bond order of this ion is 3.

The bond order of O2 molecule is 2, so the O–O bond in O22+ ion is stronger.

Which of the following complexes would be diamagnetic (displayno magnetism). Question 18 options: A) High-spin [Co(H2O)6]3+ B)Low spin [Fe(NH3)6]3+ C) Strong-field [Cr(H2O)5(CN)] D)[Zn(NH3)6]2+ E) [TiCl4(NH3)2]-

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