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Calculate the pH after 0.020 mol of HCl is added to 1.00 L of each of the following solutions.

(a) 0.100 M propanoic acid (HC3H5O2, Ka = 1.3×10-5)

(b) 0.100 M sodium propanoate (NaC3H5O2)

(c) pure water

(d) a mixture containing 0.100 M HC3H5O2 and 0.100 M NaC3H5O2

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Patrick SuarezLv10
25 Oct 2020
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Related questions

What is the pH after 0.020 mol HCl is added to 1.00 L of 0.100 M HONH2 (Kb = 1.1 x 10-8)?

A 1.38 L buffer solution consists of 0.100 M butanoic acid and 0.334 M sodium butanoate. Calculate the pH of the solution following the addition of 0.078 moles of NaOH. Assume that any contribution of the NaOH to the volume of the solution is negligible. The Ka of butanoic acid is 1.52 × 10-5.

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A 1.30 L buffer solution consists of 0.274 M propanoic acid and 0.107 M sodium propanoate. Calculate the pH of the solution following the addition of 0.064 moles of HCl. Assume that any contribution of the HCl to the volume of the solution is negligible. The Ka of propanoic acid is 1.34 × 10-5.

Calculate the pH for the following solutions:

a. A solution prepared by diluting 50.0 mL of 1.00 M HCl with enough water to bring the final volume to 2.50 L.

b. A solution that is prepared by mixing 1.00 L of 0.250 M HOBr (hypobromic acid) with 0.500 L of 0.100 M sodium hydroxide (Ka of HOBr = 2.3 x 10-9).

c. A solution that is prepared by mixing 1.00 L of 0.250 M OBr– (hypobromite ion) with 0.500 L of 0.100 M hydrochloric acid (Ka of HOBr = 2.3 x 10-9).

d. A solution that is prepared by mixing 1.00 L of 0.250 M HOBr (hypobromic acid) with 0.500 L of 0.100 M OBr– (hypobromite ion) (Ka of HOBr = 2.3 x 10-9).

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