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How would you account for the trend in the values of ionization energies for aluminum? Why is there is a large increase between I3 and I4?

Al(g) Al+(g) + e-         I1 = 580 kJ/mol

Al+(g)  Al2+(g) + e-     I2 = 1815 kJ/mol

Al2+(g)  Al3+(g) + e-   I3 = 2740 kJ/mol

Al3+(g)  Al4+(g) + e I4 = 11600 kJ/mol

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Joseph De Leon
Joseph De LeonLv10
25 Dec 2020

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