An ionized oxygen molecule (O⁺₂) at point A has charge +e and moves at 2.00×10³ m/s in the positive x-direction. A constant electric force in the negative x-direction shows the molecule to a stop at point B, a distance of 0.750 mm past A on the x-axis. Calculate (a) the x-component of the electric field and (b) the potential difference between points A and B.

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Bryllant BaluyutLv10

5 Nov 2020

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An ionized oxygen molecule (O⁺₂) at a point charge A has charge +e and moves at 2x10³ m/s in the positive x-direction. A constant electric force in the negative x-direction slows the molecule to stop at point B, a distance of 0.750 mm past A on the x-axis.

a. Calculate the x-component of the electric field and

b. the potential difference between points A and B.

blushmammoth735

Two point charges are placed on the x axis. The first charge,q_1 = 8.00 nC, is placed a distance 16.0 m from the origin alongthe positive x axis; the second charge, q_2 = 6.00 nC, is placed adistance 9.00 m from the origin along the negative x axis.Calculate the electric field at point A, located at coordinates(0m, 12.0 m).

E_Ax, E_ Ay=0,0.300 N/C Correct

I need help in Part B

Part B) An unknown additional charge q_3 is now placed at pointB, located at coordinates (0 m, 15.0 m). Find the magnitude andsign of q_3 needed to make the total electric field at point Aequal to zero.

Express your answer in nanocoulombs to three significantfigures