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What is the minimum price to boil 1 liter of water using LPG gas? LPG contains 40% propane and 60% butane  

ΔH°f   = -96 kJ/mol
ΔH°f   = -68.4 kJ/mol
ΔH°f   = -25.6 kJ/mol
ΔH°f   = -28 kJ/mol
Heat capacity of water =  

The price of LPG gas in a 3 kg cylinder = IDR 20,000

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Related questions

Propane, C3H8, is a hydrocarbon that is commonly used as fuel.

a. Write a balanced equation for the complete combustion of propane gas.

b. Calculate the volume of air at 25°C and 1.00 atmosphere that is needed to completely combust 25.0 grams of propane. Assume that air is 21.0 percent O2 by volume. (Hint: 1.00 L of air at 25°C and 1.00 atm contains 0.275 g of O2 per liter).

c. The heat of combustion of propane is -2219.2 kJ/mol. Calculate the heat of formation, ΔH°f of propane given that ΔH°f of H2O(l) = -285.8 kJ/mol and ΔH°f of Co2(g) = -393.5 kJ/mol.

d. Assuming that all of the heat released in burning 25.0 g of propane is transferred to 4.00 kilograms of water, calculate the increase in temperature of the water.


1.A system releases 691 kJ of heat and does 100 kJ of work on the surroundings.

What is the change in internal energy of the system? Express your answer to 2 sig figs.

2.If 1.7 g of matter were converted to energy, how much energy would be formed?

Express your answer using two significant figures.

3.Hydrogen gas reacts with oxygen to form water.

2H2(g)+O2(g)→2H2O(g)ΔH=−483.5kJ

Determine the minimum mass of hydrogen gas required to produce 524 kJ of heat.

Express your answer to three significant figures and include the appropriate units.

4. Calculate ΔHrxn for the following reaction:
5C(s)+6H2(g)→C5H12(l)
Use the following reactions and given ΔH′s.
C5H12(l)+8O2(g)→5CO2(g)+6H2O(g), ΔH= -3244.8 kJ
C(s)+O2(g)→CO2(g), ΔH= -393.5 kJ
2H2(g)+O2(g)→2H2O(g), ΔH= -483.5 kJ

Express answer to 4 sig figs.

5.

Use the ΔH°f and ΔH°rxn information provided to calculate ΔH°f for IF:

ΔH°f (kJ/mol) IF7(g) + I2(g) → IF5(g) + 2 IF(g) ΔH°rxn = -89 kJ
IF7(g) -941
IF5(g) -840
a.101 kJ/mol
b.-146 kJ/mol
c. -190 kJ/mol
d. -95 kJ/mol
e. 24 kJ/mol

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