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What is the balanced chemical equation for this reaction?

 

a. Enter the coefficients for each compound in order, separated by commas. (2,25,16,18)

b. 0.280 mol of octane is allowed to react with 0.630 mol of oxygen. Which is the limiting reactant? (Oxygen)

c. How many moles of water are produced in this reaction? (0.454 mol)

d. After the reaction, how much octane is left?

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7 Jan 2021

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Related questions

Determine the balanced chemical equation for this reaction.

 

A. Enter the coefficients for each compound in order, separated by commas.

B. 0.280 mol of octane is allowed to react with 0.630 mol of oxygen. Which is the limiting reactant?

C. How many moles of water are produced in this reaction?

D. After the reaction, how much octane is left?

Part A

Determine the balanced chemical equation for this reaction.

C8H18(g)+O2(g)?CO2(g)+H2O(g)

Enter the coefficients for each compound in order, separated by commas. For example, 1,2,3,4 would indicate one mole of C8H18, two moles of O2, three moles of CO2, and four moles of H2O.

2,25,16,18

Balanced chemical equation

2C8H18(g)+25O2(g)?16CO2(g)+18H2O(g)

Part B

0.240 mol of octane is allowed to react with 0.610 mol of oxygen. Which is the limiting reactant?

oxygen

Part C

How many moles of water are produced in this reaction?

Express your answer with the appropriate units.
H2O produced =

Part D

After the reaction, how much octane is left?

Express your answer with the appropriate units.

After the reaction, how much octane is left?

2 C8H18 + 25 O2 --> 16 CO2 + 18 H2O

0.660 mol of octane is allowed to react with 0.780 mol of oxygen. Oxygen is the limiting reactant.
After the reaction, how much octane is left?

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