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3 Feb 2019
Consider the following IS-LM Model
C = 189 + 0.52Yd
I = 145 + 0.12Y - 1025i
G = 329
T = 263
(M/P)^d = 1.6Y - 7737i
M/P = 1579
The IS equation is determined to be Y=1461.78-2847.22i
The LM equation is determined as i=-0.20408+0.00021Y
Initial equilibrium values of Y,i,c, and I are calculated bellow.
Y=1278
i=6.43%
C=717
I=232
Suppose that money supply increases to (m/p)=1737
Calculate the equation for the new LM relation.
i=-0.22451+0.00021Y
1. giving the above IS-LM equation, what is the equilibrium output(Y) interest(i)?
what is the equilibrium value of C?
what is the equilibrium value of I ?
DETERMINE THE VALUE OF C+I+G? round answer to the nearest integer.
Consider the following IS-LM Model
C = 189 + 0.52Yd
I = 145 + 0.12Y - 1025i
G = 329
T = 263
(M/P)^d = 1.6Y - 7737i
M/P = 1579
The IS equation is determined to be Y=1461.78-2847.22i
The LM equation is determined as i=-0.20408+0.00021Y
Initial equilibrium values of Y,i,c, and I are calculated bellow.
Y=1278
i=6.43%
C=717
I=232
Suppose that money supply increases to (m/p)=1737
Calculate the equation for the new LM relation.
i=-0.22451+0.00021Y
1. giving the above IS-LM equation, what is the equilibrium output(Y) interest(i)?
what is the equilibrium value of C?
what is the equilibrium value of I ?
DETERMINE THE VALUE OF C+I+G? round answer to the nearest integer.
Reid WolffLv2
3 Feb 2019