2
answers
0
watching
38
views
16 Sep 2022
PCl5(s) + H2O (g) ? 2HCl (g) +POCl3 (g)[[Keq= 11]]
At equilibrium, the 4.0Lflask contains the indicated amounts of the threechemicals.
PCl5 = .012M H2O = .016M HCl = .120 M
PCl5(s) + H2O (g) ? 2HCl (g) +POCl3 (g)[[Keq= 11]]
At equilibrium, the 4.0Lflask contains the indicated amounts of the threechemicals.
PCl5 = .012M H2O = .016M HCl = .120 M
inamjazbiLv3
16 Sep 2022
Unlock all answers
Get 1 free homework help answer.
Already have an account? Log in
phwxnq25Lv10
16 Sep 2022
Get unlimited access
Already have an account? Log in