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13 Dec 2019

1. ________ is the oxidizing agent in the reaction below.


Cr2O72- + 6S2O32- + 14H+ ? 2Cr3+ + 3S4O62- + 7H2O

Cr3+
S2O32-
H+
S4O62-
Cr2O72-

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Patrina SchowalterLv2
17 Dec 2019
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Related questions

Refer to the cell below:

Pt | Cr3+(0.40 M), Cr2O72-(0.30 M), H+(0.010M) || MnO4-(0.10 M),Mn2+(0.20 M), H+(0.010M) | Pt

The standard reduction potentials are as follows:

MnO4- + 8H+ + 5e- ----> Mn2+ + 4H2O; Eo = +1.51 V

Cr2O72- + 5e- -----> 2Cr3+ + 7H2O; Eo = +1.33 V

When current is allowed to flow, which species is reduced?

Refer to the cell below:

Pt | Cr3+(0.40 M), Cr2O72-(0.30 M), H+(0.010M) || MnO4-(0.10 M),Mn2+(0.20 M), H+(0.010M) | Pt

The standard reduction potentials are as follows:

MnO4- + 8H+ + 5e- ---> Mn2+ + 4H2O; Eo = +1.51 V Cr2O72- +5e- ----> 2Cr3+ + 7H2O; Eo = +1.33 V

What is the value of Eocell? Select one:

a. -0.18 V

b. +2.84 V

c. +0.18 V

d. +1.79 V

e. +2.29 V

Here is a more complex redox reaction involving the dichromate ion in acidic solution:

3NO2− + 8H+ + Cr2O72− → 3NO3− +2Cr3+ + 4H2O

Classify each reactant as the reducing agent, oxidizing agent, or neither.

NO2− H+ Cr2O72-

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