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Chemistry
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13 Dec 2019

Which of the following Km values for the binding of substrate to a particular enzyme would display an enzyme that has the lowest affinity for the substrate?

0.015 mM
1500 mM
15 mM
150 mM
0.15 mM

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Jean Keeling
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17 Dec 2019
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Related questions

To study the kinetics of this enzyme, a graduate student measured the velocity of the reaction at a substrate concentration of 0.1 mM substrate. He found that after 1 mM competitive inhibitor was added, the initial rate decreased to 1/4 of the original rate. KM, the Michaelis constant, is 0.5 mM. What is the KI, the dissociation constant for the inhibitor binding to the enzyme? (Hint: in the presence of the competitive inhibitor, Vo= Vmax [S]/(1+[I]/KI) KM+ [S])

The answer is 0.28 mM, please give a detailed explanation

Can someone explain how to go about solving this?


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