12 Nov 2021
Problem 11a
Page 252
Section: Problems
Chapter 9: Static Equilibrium; Elasticity And Fracture
Textbook ExpertVerified Tutor
12 Nov 2021
Given information
Given:
Mass of adult 
.
.Mass of child 
.
.Length of board 
.
.Step-by-step explanation
Step 1.
The pivot should be placed so that the net torque on the board is zero. We calculate torques about the pivot point, with counterclockwise torques positive. The upward force
at the pivot point is shown, but it exerts no torque about the pivot point. The mass of the child is 
, the mass of the adult is 
, the mass of the board is 
, and the center of gravity is at the middle of the board.
at the pivot point is shown, but it exerts no torque about the pivot point. The mass of the child is , the mass of the adult is , the mass of the board is , and the center of gravity is at the middle of the board.
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Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922
Solutions
Chapter
Section
- Problem 1
- Problem 2
- Problem 3a
- Problem 3b
- Problem 4
- Problem 5a
- Problem 5b
- Problem 6
- Problem 7
- Problem 8a
- Problem 8b
- Problem 9
- Problem 10
- Problem 11a
- Problem 11b
- Problem 12
- Problem 13
- Problem 14
- Problem 15
- Problem 16
- Problem 17
- Problem 17
- Problem 18
- Problem 19a
- Problem 19b
- Problem 20
- Problem 21
- Problem 22a
- Problem 22b
- Problem 22c
- Problem 23
- Problem 24
- Problem 25a
- Problem 25b
- Problem 26
- Problem 27a
- Problem 27b
- Problem 27c
- Problem 28
- Problem 29
- Problem 30
- Problem 31
- Problem 32
- Problem 33
- Problem 34a
- Problem 34b
- Problem 35
- Problem 36
- Problem 37
- Problem 38
- Problem 39a
- Problem 39b
- Problem 39c
- Problem 39d
- Problem 40
- Problem 41a
- Problem 41b
- Problem 42
- Problem 43a
- Problem 43b
- Problem 43c
- Problem 44
- Problem 45
- Problem 46
- Problem 47
- Problem 48
- Problem 49
- Problem 50
- Problem 51a
- Problem 51b
- Problem 52a
- Problem 52b
- Problem 53a
- Problem 53b
- Problem 54
- Problem 55
- Problem 56
- Problem 57
- Problem 58
- Problem 59a