16 Nov 2021
Problem 19
Page 621
Section: Problems
Chapter 21: Electromagnetic Induction and Faraday’s Law
Textbook ExpertVerified Tutor
16 Nov 2021
Given information
Diameter of loop=13.2 cm
Radius of loop = d/2
=6.6 cm
= 0.066 m
Magnetic field (B)=0.670 T
Diameter wire =2.25 mm
Radius wire= d/2
Step-by-step explanation
Step 1.
Formulas to be used:
By combining the equations
The charge with respect to elapsed time
Q=It …… (1)
By ohm’s law, the induced current
…… (2)
The resistance is given by,
[Aw= Area of wire]...... (3)
By Faraday’s law, the induced emf is given by,
[
=Area of loop]……(4)
Combining the equations (2), (3) and (4)
……(5)
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Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922
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