Textbook ExpertVerified Tutor
25 Nov 2021
Given information
mass of atomic nucleus=
velocity of the nucleus=
After collision final velocity of nucleus will be 
mass of target particle= 
initial velocity of target particle= 
Angle at which target particle is scattered=
The collision is elastic.
Step-by-step explanation
Step 1.
Applying the law of conservation for elastic collision, we get
equation of momentum along x-axis
similarly equation of momentum along y axis
Squaring and adding both the equations we get
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Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922
Solutions
Chapter
Section
- Problem 1
- Problem 2
- Problem 3
- Problem 4
- Problem 5
- Problem 6
- Problem 7
- Problem 8
- Problem 9
- Problem 10
- Problem 11
- Problem 12
- Problem 13
- Problem 14a
- Problem 14b
- Problem 15
- Problem 16a
- Problem 16b
- Problem 17a
- Problem 17b
- Problem 18
- Problem 19a
- Problem 19b
- Problem 19c
- Problem 20
- Problem 21a
- Problem 21b
- Problem 21c
- Problem 21d
- Problem 22
- Problem 23a
- Problem 23b
- Problem 24a
- Problem 24b
- Problem 24c
- Problem 25
- Problem 26
- Problem 27
- Problem 28
- Problem 29a
- Problem 29b
- Problem 30
- Problem 31a
- Problem 31b
- Problem 32a
- Problem 32b
- Problem 32c
- Problem 32d
- Problem 33
- Problem 34a
- Problem 34b
- Problem 35
- Problem 36
- Problem 37
- Problem 38
- Problem 39
- Problem 40
- Problem 41a
- Problem 41b
- Problem 42
- Problem 43a
- Problem 43b
- Problem 44a
- Problem 44b
- Problem 45
- Problem 46
- Problem 47a
- Problem 47b
- Problem 47c
- Problem 48
- Problem 49
- Problem 50
- Problem 51
- Problem 52
- Problem 53
- Problem 54
- Problem 55
- Problem 56
- Problem 57
- Problem 58
- Problem 59
- Problem 60
- Problem 61a
- Problem 61b
- Problem 62
- Problem 63a
- Problem 63b
- Problem 63c
- Problem 64a
- Problem 64b
- Problem 65
- Problem 66