blushfly648Lv1
2 Dec 2021
Problem 71a
Page 73
Section: General Problems
Chapter 3: Kinematics In Two Dimensions; Vectors
Textbook ExpertVerified Tutor
2 Dec 2021
Given information
Basketball is shot from an initial height of with an initial speed directed at an angle above the horizontal.
Step-by-step explanation
Step 1.
Horizontal component of velocity is . Here is initial velocity and is the angle made with horizontal.
So the horizontal component of velocity is , As the value of
Now we will find the time to basket , for this we use equation of motion
Here is the component of velocity in vertical direction. its value is
We will consider the height above launch height i.e.
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