ï»¿ï»¿ï»¿ï»¿Lets say you've a crystal ball, on one side we cast coloredglass. For which refractive index, the image of crystal grain wouldappear in infinity, when you look from the other side (not colored)of the crystal ball?

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find D, L, y, Î».

Electrons are incident on a double slit and pass through toascreen as shown. Each of the five animations gives a snapshotofthe data collected at a later time period. If the slitis0.08-microns wide and the distance to the screen is 1.2 m, whatisthe de Broglie wavelength of the electron (signal isincounts of 100 and the position on the screen is giveninmm).

Here is an Image of time 5

You can view the other times on Problem 5.7 onthislink:

http://homepages.ius.edu/kforinas/modern/contents/need_quantum/waves_particles/default.html

Hint: use equation: I=I₀sin²(ÏDy/Î»L)/(ÏDy/Î»L)²and solve for value of y when I first goesto zero.Remeber that y is the distance from center on the screen,which theanimation refers to as x.

This has been bothering me for a long time and I cant find anadequate explanation..

Lets say you have an infinite conducting plate with finitethickness D and it is given charge Q

the charge will be equally split into two and concentrated only onthe two surfaces.

Each surface will get Q/2

and the magnitude of electric field outside the plate isE=Q/(2A*epsilon naught) (E for a conducting plate is surface chargedensity/epsilon naught as opposed to surface chargedensity/(2epsilon naught)

Then, if you have two nonconducting plates separated by distance Dand each plate gets Q/2 which is uniformly distributed ..
then outside the space between the two plates, E = 2*(Q/4A*epsilonnaught)

But why cant we use superposition principle in the case of oneconducting plate with Q and say you get E=Q/(A epsilon naught)i.e.Q/(2A epsilon naught) from each surface...

Is it because we are looking at the mid section of the conductor assome kind of Faraday cage? (since the plate is essentially infinityand blocks the electric field from the other side?)

Also, lets look at two parallel plate capacitor..

One plate gets +Q/2 and the other gets -Q/2

I know the formula says E= charge density/epsilon naught.. so E hasto be Q/(2A epsilon naught) However, it seems rather inconsistentin the case of the parallel plate capacitor...

We know all the charge is going to be concentrated on the innersurface
So shouldnt you get E = Q/(2A epsilon naught) solely from one plateand since you have TWO plates!!!, shoudlnt you multiply Q/(2Aepsilon naught) by 2?

find D, L, y, Î».

In this animation, electrons are incident on a double slitandpass through to a screen as shown. Each of the fiveanimationsgives a snapshot of the data collected at a later timeperiod. Ifthe slit is 0.08-microns wide and the distance tothe screen is 1.2m, what is the de Broglie wavelength of theelectron (signalis in counts of 100 and the position onthe screen is given inmm).

Here is an Image of time 5

You can view the other times on Problem 5.7 onthislink: ( i dont think they are needed)

http://homepages.ius.edu/kforinas/modern/contents/need_quantum/waves_particles/default.html

I'm not sure how to approach this problem..can any1 helpmeout???

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ï»¿ï»¿ï»¿ï»¿Lets say you've a crystal ball, on one side we cast coloredglass. For which refractive index, the image of crystal grain wouldappear in infinity, when you look from the other side (not colored)of the crystal ball?

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Physics: Principles with Applications

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