Log in
Physics
1
answer
0
watching
203
views
23 Nov 2019

http://session.masteringphysics.com/problemAsset/1070346/12/05.P31.jpg

I have attempted this many times on mastering physics but i onlyhave one chance to answer left. I dont know what im doing wrong. iintegrated a to get v and then v to get x.

Watch
1
answer
0
watching
203
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Keith Leannon
Keith LeannonLv2
31 Aug 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Share

Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

<div class="content">I need to find the How much heat isrequired for process A and B?<br /><br />For theProcess A, it is constant vouleme, so I get Q=1.014219013.... J forthe first one, but my friends have -1000J So, I think my equation:Q=Cv(vp_2-vp_1)/R may be wrong... please help me :)<br/><br />This is the diagram: <a rel="nofollow"href="http://session.masteringphysics.com/problemAsset/1070978/5/17.P57.jpg">http://session.masteringphysics.com/prob&#8230;</a>
<div class="asset"><imgsrc="http://session.masteringphysics.com/problemAsset/1070978/5/17.P57.jpg"alt="17.P57.jpg" width="320" height="260" /></div>
<br /><br />Also I have no idea what to do with thepart B....</div>

Sources A and B emit long-range radio waves of wavelength 450 m,with the phase of the emission from A ahead of that from source Bby 90°. The distance rA from A to a detector is greater than thecorresponding distance rB from B by 87 m. What is the magnitude ofthe phase difference at the detector in rad?

I dont know what im doing wrong?
I take x/?=phase difference /360 degrees
so the corresponding phase difference= 360*87/450 = 69.6degree
hence the phase difference at the detector= 90+69.6 =159.6degree.

then converting to rad, 159.6 (pi/180 deg) = 2.7855 rad but wileykeeps saying that this answer is wrong? please help.

We are doing an experiment in my physics lab that involves trying to find the horizontal component of the Earth's magnetic field. Here is a little explanation of what is going on: We have a bar magnet that is placed inbetween a set of Helmholtz coils (125 of them coiled) and we place a certain current (i) on the coils. We then see that the bar magnet begins to try to align itself with the magnetic field, but it will have an angular momentum that will cause it to continue turning past the direction of the magnetic field creating oscillations. Our instructor told us to count 25 oscillations and find the time it takes for 25 to occur. From that we can then find the period of oscillations(T) from each current. Then we can find 1/T^2 from this. We then plot a graph with current(i) on the x-axis and 1/T^2 on the y axis and we find its a straight linear line. Our Instructor stated that the y-intercept will be our b and our slope will be S. From the equation given in our packet which is: (32pN x 10^-7/r x radical 125) x b/S. I know that N is the number of coils, r is the radius(9.6cm), b is the y-intercept, and S is the slope. However, from my graph, my equation for the line of best fit was y=0.967x - 0.3068. plugging this in (32p(125) x 10^-7/9.6cmx radical 125) x (.3068/.967) I get 4.643x10^-4. Putting this into gauss by multiplying times (10^4) i get 4.64 which i know is far off since NASA says its around 0.2-0.5 gauss average around Earth. I would really appreciate the help for what im doing wrong.

Weekly leaderboard

Home
Homework Help 3,900,000
Physics 110,000
Start filling in the gaps now
Log in