BIOL 1000 Lecture Notes - Lecture 46: Allele Frequency, Foot, Genotype Frequency
13 May 2017
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800/1000 x 100 = 80%) p = . 80, q = . 20 (p + q = 1: probability of producing a ww individual is p x p = . 80 x . 60 = . 64. Ww individual probability is 2pq = 2 x . 08 x . 02 = . 32. Multiply by 2 because this genotype can result from the sperm carrying w and eggs carrying w. Or from sperm carrying w and egg carrying w. Gene pool remains at state of equilibrium p2 + 2pq + q2 = 1. Frequency of homozygous dominants + frequency of heterozygotes + frequency of homozygous recessives = 1. For a population to be in hardy-weinberg equilibrium it must satisfy 5 conditions: : very large population. Smaller the population, more likely that allele frequencies will fluctuate by chance between generations: no gene flow between populations. When people move in/out of populations they add/remove alleles, altering the gene pool: no mutations pool .
