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John CayasUniversity of the Philippines Diliman

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Graduate of Bachelor of Science in Civil Engineering

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Chemistry79
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1. 62.0 mL of 8.5 (m/v)% KClKCl (MW = 74.55 g/mol)
Express your answer using two significant figures.
 
2.250.0 mL of 9.0 (m/v)% acetic acid (MW = 60.05 g/mol)
Express your answer using two significant figures.
 
3.If you had only 25 g of KOHKOH remaining in a bottle, how many milliliters of 6.5 %(w/v) solution could you prepare?
Express your answer using two significant figures.
 
4.How many milliliters of 0.17 M solution could you prepare?
Express your answer using two significant figures.
 
5.Calculate the mass percent (m/m) of a solution prepared by dissolving 46.79 g of NaCl in 160.5 g of H2O.
Express your answer to four significant figures.
 
6.Calculate the mass percent (m/m) of a solution prepared by dissolving 46.79 g of NaCI in 160.5 gg of H2O.
Express your answer to four significant figures.
 
7.Calculate the mass/volume percent (m/v) of 14.0 g NaCl in 61.5 mL of solution.
Express your answer to three significant figures.
 
8.Calculate the molarity (MM) of 153.5 g of H2SO4 in 1.085 L of solution.
Express your answer to four significant figures.
 
9.What is the boiling point of a solution made using 827 g of sucrose, C12H22O11, in 0.200 kg of water, H2O?
 
10.What is the freezing point of a solution that contains 29.5 g of urea, CO(NH2), in 205 mL water, H2O? Assume a density of water of 1.00 g/mL.
 
11.Given the formula C1V1=C2V2, where C indicates concentration and V indicates volume, which equation represents the correct way to find the concentration of the dilute solution (C2)?
 
12.What is the final volume V2 in milliliters when 0.935 L of a 48.0 %(m/v) solution is diluted to 24.7 % (m/v)?
 
13.A 738 mL NaCl solution is diluted to a volume of 1.15 L and a concentration of 3.00 MM. What was the initial concentration C1?
Express your answer with the appropriate units.
 
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We can determine the empirical formula of the compound just by using the perce...
In the problem, the quantity being asked is the molarity of that will be used ...

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