poptropica

Point out four limitations of chemical equation

• Problem Statement

Assume that there are two teams and they are team attacker and team defender. Therefore, at a state of the game one agent in each team is left alive respectively. Here, the defender is given a lifeline called HP which will be assigned randomly. Furthermore, the attacker agent will try to give maximum negative HP to the defender agent to decrease his(d) chances of survival in the game. On the other hand, the defender agent will try to protect himself by receiving the lowest negative HP possible from the attacker agent. Furthermore, the attacker can have a choice from a number of bullets from his gun and the optimal moves will cost a certain maximum negative HP (chosen from randomly assigned values within the range of minimum and maximum negative HP). Here, are the following things you need to do using Alpha-Beta Pruning algorithm:

• Sample Input 1:

1. Enter your student id:

17301106

1. Minimum and Maximum value for the range of negative HP:

1 30

Note: Here, the second input is a space separated single line input string.

• Sample Input 1 Explanation:

Ex. 1 (17301106)

(Use 1st digit of your bracu student id)

# Number of turns for the attacker agent

[Assume that both of them will get equal number of chances]

Ex. 60 (17301106)

(Use last 2 digits of your bracu student id in reverse)

# Initial lifeline (HP) for the defender at initial state of the game

Ex. 3 (17301106)

(Use semester code-3rd digit of your bracu student id)

# Number of bullets from which the final choice has to be made by the attacker.

Ex. 1 (1 30)

# Minimum value for the range of negative HP values

Ex. 30 (1 30)

# Maximum value for the range of negative HP values

• Sample Output 1:

1. Depth and Branches ratio is 2:3
2. Terminal States (leaf node values) are 19,22,9,2,26,16,16,27,16.
3. Left life(HP) of the defender after maximum damage caused by the attacker is 44
4. After Alpha-Beta Pruning Leaf Node Comparisons 7

• Sample Output 1 Explanation:

(Application of Alpha-Beta Pruning Algorithm)

MAX            - Level 0                    Attacker’s Turn / Initial Start                     MAX utility/Best Choice

MIN             - Level 1                       Defender’s Turn                                     3 branches

Leaf Nodes - Level 2                         Terminal state                                       3^2=9 Leaf Nodes(Random States)

                                                                                                                                  [19, 22, 9, 2, 26, 16, 16, 27, 16]

(Left lifeline/HP)

Left Life = (60 - 16) = 44

So, Left life(HP) of the defender after maximum damage caused by the attacker is 44

Hint:

1. Apply Alpha-Beta Pruning algorithm for sample output line 3 and line 4
2. Formula: Left life HP=Initial life HP-MAX negative HP

Note:

Terminal nodes are randomly generated values within the given range of negative HP (sample output line 2).

• Sample Input 2:

1. Enter your student id:

20201003

1. Minimum and Maximum value for the range of negative HP:

5 20

• Sample Output 2:

1. Depth and Branches ratio is 4:2
2. Terminal States(Leaf Nodes) are 18,13,5,12,10,5,13,7,17,8,6,8,5,11,13,18.
3. Left life(HP) of the defender after maximum damage caused by the attacker is 22
4. After Alpha-Beta Pruning Leaf Node Comparisons 13

Assume Initial values of the registers are as follow:

$t0 =0x00000000, $t1 = 0x0000000F, $t2 = 0x00000005, $t3 =0x0000000A

$s0 =0x000000FC, $s1= 0x000000A1

1. Translate the instructions from Hex code to MIPS assembly code

2. Complete the control signals in the table according to each instruction.

3. What is the value of these registers after execution of the instructions?

Design and code a method for the class
SinglylLinkedList called deDuplicate() that will
remove duplicates from the list according to
value. The method should return the number of
items deleted. You may assume that a
delete(item) method already exist.
Example list before deDuplicate():
5; 3;4;3;6;3;4;
After:
5; 3;4;6 removed 3 elements
(The order of the remaining numbers may differ.)

Consider the following MIPS instructions, assume the following cycle times for each of the
options related to forwarding:
Without Forwarding: 130ns
With full Forwarding: 200ns
With ALU-ALU Forwarding: 180ns

1. Draw the pipeline execution diagram for this code and indicate hazards, assume there is
no forwarding in this pipelined processor.
2. Draw the pipeline execution diagram for this code and indicate hazards, assume there is
full forwarding in this pipelined processor.
3. What is the total execution time of this instruction sequence without forwarding and with
full forwarding? What is the speedup achieved by adding full forwarding to a pipeline
that had no forwarding?
4. What is the total execution time of this instruction sequence with only ALU-ALU
forwarding? What is the speedup over a no-forwarding pipeline?

Dow Chemicals DOW acquisition of Rohm Haas ROH in 2008 For this entire question use only the information given herein. Assume that the value of synergies is 5 billion. Disregard personal taxes. DOW has 936 million shares outstanding and ROH has 195.2 million shares outstanding. The pre-merger stock prices of DOW and ROH were 33.96 and 44.83 respectively.

 a. If DOW pays cash 78 per share for each of the 195.2 million shares of ROH what is the distribution of the synergy between the original stockholders of DOW and the stockholders of ROH?

b. Now assume that DOW announces the offer to purchase ROH for 78 cash per ROH share. The post-announcement stock price of DOW and ROH is 32.52 and 73.62 respectively. Assuming that the final outcome of the offer will be known in 1 year and the one-year interest rate is 3. What would be the strategy of a merger arbitrager who believes that the deal will eventually be completed successfully as proposed?

d. Suppose that instead of cash the offer is an all-stock offer with an exchange ratio is 2.50 for 1 and that the post-announcement market reaction is still the same as in b above. What would be the strategy of a merger arbitrager who believes that the deal will eventually be completed successfully as proposed?

Draw the structure of the compound C8H9BrO that exhibits the 13C-NMR spectrum and DEPT data below. Impurity peaks are omitted from the DEPT data list. The triplet at 77 ppm is CDCl3.

Theyre all one peak except for one

The proton NMR spectrum for a compound with the formula C5H12O is shown below along with the spectral data in tabular form. (It may be necessary to expand (zoom) some of the 1H signals to view spin-spin splitting details.)

When negotiating with a vendor you use a lot, what might be your business request?

A. Moving from Net-10 payments to Net-15

B. Less products

C. Moving from Net-60 to Net -10

D. Instead of cash payments they receive your product as a payment

The proton NMR spectrum of a compound with formula C7H12O2 is shown. The infrared spectrum displays a strong band at 1738 cm−1 and a weak band at 1689 cm−1
. The normal carbon-13 and the DEPT experimental results are tabulated. Draw the structure of this compound.

When negotiating with a vendor you use a lot, what might be your business request ?

A. Moving from Net-10 payments to Net-15

B. Less products

C. Moving from Net-60 to Net -10

D. Instead of cash payments they receive your product as a payment.

Why do firms use the Accounts Payable Schedule?

A. To know the due date of their debts.

B. To predict interest payments on loans.

C. To report and track monthly costs.