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22 Oct 2021

Given information

Researcher A: 3; 4; 11; 15; 16; 17; 22; 44; 37; 16; 14; 24; 25; 15; 26; 27; 33; 29; 3; 44; 13; 21; 22; 10; 12; 8; 40; 32; 26;
27; 31; 34; 29; 17; 8; 24; 18; 47; 33; 34

Frequency is the number of time the data occurs.Here the Data of 40 AIDS patients representing interval of 6 in each row so we have to find frequency by Tally method

Researcher A Table

Tally method of Frequency=total number lies in that interval

here 3, 4 survival patient lies between 0.5-6.5 interval so it frequency becomes 2, there are 5 NO. of survival lies between 6.5-12.5 so its frequency will become 5

Survival length(in months) No. of survival(tally method) Frequency
0.5-6.5 || 2
6.5-12.5 |||| 5
15.5-18.5 |||| |||| 10
18.5-24.5 |||| 4
24.5-30.5 |||| || 7
30.5-36.5 |||| || 7
36.5-42.5 || 2
42.5-48.5 ||| 3
    Total=40

 

Step-by-step explanation

Step 1.

For Relative Frequency

Relative Frequency is the fraction of frequency of that class to the total frequency

 

Relative Frequency=Frequency of the Class/Total frequency

Survival length(in months) Frequency Relative Frequency
0.5-6.5 2 2/40=0.05
6.5-12.5 5 5/40=0.125
12.5-18.5 10 10/40=0.25
18.5-24.5 4 4/40=0.1
24.5-30.5 7 7/40=0.175
30.5-36.5 7 7/40=0.175
36.5-42.5 2 2/40=0.05
42.5-48.5 3 3/40=0.075
  Total=40  
42.5-48

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