Textbook ExpertVerified Tutor
5 Nov 2021
Given information
Here, Sample size(n)=100;
The lowest actual weight=24, and the highest actual weight=26;
Step-by-step explanation
Step 1.
So, from the given information,
mean of the distribution (μx)=(24+26)/2=25; So,
& standard deviation(σx);
σx=0.5774;
So,
So, the distribution for the mean weight of 100 25-pound liftings weight=
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Introductory Statistics
OER Edition, 2013
Openstax
ISBN: 9781938168208
Solutions
Chapter
Section
- Problem 1
- Problem 2a
- Problem 2b
- Problem 3a
- Problem 3b
- Problem 4a
- Problem 4b
- Problem 5
- Problem 6a
- Problem 6b
- Problem 7
- Problem 8
- Problem 10
- Problem 10
- Problem 11
- Problem 12
- Problem 13
- Problem 14
- Problem 15
- Problem 16
- Problem 17
- Problem 18
- Problem 19
- Problem 20
- Problem 21
- Problem 22
- Problem 23
- Problem 24
- Problem 25
- Problem 26
- Problem 27
- Problem 28
- Problem 29
- Problem 30
- Problem 31
- Problem 32
- Problem 33
- Problem 34
- Problem 35
- Problem 36
- Problem 37a
- Problem 37b
- Problem 37c
- Problem 38
- Problem 39
- Problem 40
- Problem 41
- Problem 42
- Problem 43a
- Problem 43b
- Problem 44
- Problem 45
- Problem 46
- Problem 47a
- Problem 47b
- Problem 48
- Problem 49
- Problem 50
- Problem 51
- Problem 52
- Problem 53
- Problem 54
- Problem 55
- Problem 56
- Problem 57
- Problem 58
- Problem 59
- Problem 60