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Midterm

[Exam Tutorial] Ryerson CHY113 Midterm 2007 Solutions

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Department
Chemistry
Course Code
CHY 113
Professor
all

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Description
Multiple Choice Question Version A 1 D 2 E 3 B 4 A 5 D 6 C 7 A 8 B 9 D 10 D 11 C 12 B 13 D 14 E 15 C 16 E 17 A 18 C 19 E 20 C 21 C 22 A 23 C Problem 1. Note: There are a variety of ways to solve this problem. I have shown the typical approach. Version A Assume 100 g sample -1 moles CO = 2.00 g / 44.01 gmol = 0227 moles O =299.0 g / 32.00 gmol = 3.09 P(O 2 = X PO2 t = (3.09/(3.09+0..0227))(.977 atm) = 0.970 atm P(CO )2= P –tP O2 = .977 - .970 = 0.007 atm Problem 2. Version A mole glucose = 24.5 g / 180 gmol = 0.136 moles
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