CHY 113 Study Guide - Midterm Guide: European Route E20, Joule
Document Summary
Note: there are a variety of ways to solve this problem. Assume 100 g sample moles co2 = 1. 00 g / 44. 01 gmol-1 = 0227 moles o2 = 99. 0 g / 32. 00 gmol-1 = 3. 09. Version a mole glucose = 24. 5 g / 180 gmol-1 = 0. 136 moles co2 = . 136 x (6/1) = 0. 816 mol. **this question is similar to suggested exercise 6. 49 in your text. Heat lost by the metal = heat gained by the water + heat gained by the calorimeter. Heat gained by the water = s x m x tsurr = 4. 18 jg-1oc-1 x 80. 0 g x 4. 4 oc = 1471 j. Heat gained by the calorimeter = c x tsurr = 12. 4 j oc-1 x 4. 4 oc = 54. 6 j. C2h2 (g) + 5/2 o2 2 co2 (g) + h2o (l) a. Use the enthalpy of formation data supplied and the relation. H rxn: wmax = go = -1235. 2 kj.
