PCS 125 Study Guide - Quiz Guide: Parallelogram, Global Positioning System, Cross Product
Document Summary
Volume 1: we perform the indicated operations, c2 c2. Comparing both sides of the last equation 2c1 + c2 = 5 and c2 = - 1. Solving this simple 2 (cid:215) 2 system yields c1 = 3, c2 = - 1: let v = (x, y, z) be a vector that is orthogonal to u = (1, - 2, - 1). Hence we must choose x, y, z such that x = 2y + z. Calculating we find that v w = k + 10, so we take k = - 10: draw a picture. Let p1 = (- 1, 2, - 3) and p2 = (x, y, z) denote the initial and terminal points respec- tively of u. Then the coordinates of u are (x + 1, y - and (ii) be parallel to (1, 1, 0). The vector ( (cid:214) 1 set (x + 1, y - 2 , 0) and solve to find: x = (cid:214) 1.
